來源:http://blog.csdn.net/liminlu0314/article/details/8553926
此公式得解,用acos函數聽說會有點慢
//====================================================================||
// ||
// ||
// Author : GCA ||
// 6AE7EE02212D47DAD26C32C0FE829006 ||
//====================================================================||
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <climits>
#include <vector>
#include <set>
#include <map>
#include <queue>
#include <cctype>
#include <utility>
using namespace std;
#ifdef ONLINE_JUDGE
#define ll "%lld"
#else
#define ll "%I64d"
#endif
typedef unsigned int uint;
typedef long long int Int;
#define Set(a,s) memset(a,s,sizeof(a))
#define Write(w) freopen(w,"w",stdout)
#define Read(r) freopen(r,"r",stdin)
#define Pln() printf("\n")
#define I_de(x,n)for(int i=0;i<n;i++)printf("%d ",x[i]);Pln()
#define De(x)printf(#x"%d\n",x)
#define For(i,x)for(int i=0;i<x;i++)
#define CON(x,y) x##y
#define Pmz(dp,nx,ny)for(int hty=0;hty<ny;hty++){for(int htx=0;htx<nx;htx++){\
printf("%d ",dp[htx][hty]);}Pln();}
#define M 1005
#define PII pair<int,int>
#define PB push_back
#define oo INT_MAX
#define Set_oo 0x3f
#define Is_debug true
#define debug(...) if(Is_debug)printf("DEBUG: "),printf(__VA_ARGS__)
#define FOR(it,c) for(__typeof((c).begin()) it=(c).begin();it!=(c).end();it++)
#define eps 1e-6
bool xdy(double x,double y){return x>y+eps;}
bool xddy(double x,double y){return x>y-eps;}
bool xcy(double x,double y){return x<y-eps;}
bool xcdy(double x,double y){return x<y+eps;}
int min3(int x,int y,int z){
int tmp=min(x,y);
return min(tmp,z);
}
int max3(int x,int y,int z){
int tmp=max(x,y);
return max(tmp,z);
}
int n;
double pi=acos(-1.0);
struct pt{
double lon,lat;
double an,at;
}p[M];
double dis(pt a,pt b){
return acos(cos(a.lat)*cos(b.lat)*cos(b.lon-a.lon)+sin(a.lat)*sin(b.lat));
}
void solve(){
double ans=oo;
int id=-1;
for(int i=0;i<n;i++){
double mx=0;
for(int j=0;j<n;j++){
if(i==j)continue;
double tmp;
if(xdy(tmp=dis(p[i],p[j]),mx)){
mx=tmp;
}
}
if(xcdy(mx,ans)){
ans=mx;
id=i;
}
}
printf("%.2f %.2f\n",p[id].at,p[id].an);
}
double tr(double x){
return x*pi/180;
}
int main() {
ios_base::sync_with_stdio(0);
while(~scanf("%d",&n)){
for(int i=0;i<n;i++){
scanf("%lf%lf",&p[i].at,&p[i].an);
p[i].lat=tr(p[i].at);
p[i].lon=tr(p[i].an);
}
solve();
}
}
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