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uva 10366

邏輯思考題,個人感覺非常複雜,參考網路上解法AC

很難用言語解釋 看code反而比較清楚

//
// GGGGGGGGGGGGG CCCCCCCCCCCCC AAA
// GGG::::::::::::G CCC::::::::::::C A:::A
// GG:::::::::::::::G CC:::::::::::::::C A:::::A
// G:::::GGGGGGGG::::G C:::::CCCCCCCC::::C A:::::::A
// G:::::G GGGGGG C:::::C CCCCCC A:::::::::A
//G:::::G C:::::C A:::::A:::::A
//G:::::G C:::::C A:::::A A:::::A
//G:::::G GGGGGGGGGGC:::::C A:::::A A:::::A
//G:::::G G::::::::GC:::::C A:::::A A:::::A
//G:::::G GGGGG::::GC:::::C A:::::AAAAAAAAA:::::A
//G:::::G G::::GC:::::C A:::::::::::::::::::::A
// G:::::G G::::G C:::::C CCCCCC A:::::AAAAAAAAAAAAA:::::A
// G:::::GGGGGGGG::::G C:::::CCCCCCCC::::C A:::::A A:::::A
// GG:::::::::::::::G CC:::::::::::::::C A:::::A A:::::A
// GGG::::::GGG:::G CCC::::::::::::C A:::::A A:::::A
// GGGGGG GGGG CCCCCCCCCCCCCAAAAAAA AAAAAAA
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <climits>
#include <vector>
#include <set>
#include <map>
#include <queue>
#include <cctype>
#include <utility>
#include <ctime>
using namespace std;
#ifdef DEBUG
#define VAR(a,b) decltype(b) a=(b)
#define debug(...) printf("DEBUG: "),printf(__VA_ARGS__)
#define gettime() end_time=clock();printf("now running time is %.7f\n",(float)(end_time - start_time)/CLOCKS_PER_SEC);
#else
#define VAR(a,b) __typeof(b) a=(b)
#define debug(...)
#define gettime()
#endif
typedef unsigned int uint;
typedef long long int Int;
typedef unsigned long long int UInt;
#define Set(a,s) memset(a,s,sizeof(a))
#define Write(w) freopen(w,"w",stdout)
#define Read(r) freopen(r,"r",stdin)
#define Pln() printf("\n")
#define I_de(x,n)for(int i=0;i<n;i++)printf("%d ",x[i]);Pln()
#define De(x)printf(#x"%d\n",x)
#define For(i,x)for(int i=0;i<x;i++)
#define CON(x,y) x##y
#define Pmz(dp,nx,ny)for(int hty=0;hty<ny;hty++){for(int htx=0;htx<nx;htx++){\
printf("%d ",dp[htx][hty]);}Pln();}
#define M 3005
#define PII pair<int,int>
#define PB push_back
#define oo INT_MAX
#define Set_oo 0x3f
#define FOR(a,b) for(VAR(a,(b).begin());a!=(b).end();++a)
#define eps 1e-6
#define X first
#define Y second
#define gca printf("im here\n");
clock_t start_time=clock(), end_time;
bool xdy(double x,double y){return x>y+eps;}
bool xddy(double x,double y){return x>y-eps;}
bool xcy(double x,double y){return x<y-eps;}
bool xcdy(double x,double y){return x<y+eps;}
int min3(int x,int y,int z){
int tmp=min(x,y);
return min(tmp,z);
}
int max3(int x,int y,int z){
int tmp=max(x,y);
return max(tmp,z);
}
int n;
int nr,nl;
int h[M];
int al[M],ar[M];
int ans;
int lm[M],rm[M];
void solve(){
int pre=0;
al[0]=0;
lm[0]=0;
for(int i=1;i<=nl;i++){
if(h[i]>=h[pre]){
al[i]=al[i-1]+h[pre]*((i-pre)<<1);
lm[i]=pre=i;
}else{
al[i]=al[i-1];
lm[i]=pre;
}
}
pre=n;
ar[n]=0;
rm[n]=n;
for(int i=n-1;i>=nr;i--){
if(h[i]>=h[pre]){
ar[i]=ar[i+1]+h[pre]*((pre-(i))<<1);
rm[i]=pre=i;

}else{
ar[i]=ar[i+1];
rm[i]=pre;
}
}
// debug("%d %d\n",h[lm[nl]],h[rm[nr]]);
if(h[lm[nl]]<h[rm[nr]]){
// debug("ok\n");
int i=nr;
bool fg=false;
int index=-1;
for(;h[lm[nl]]>=h[i];i++){
if(!fg&&h[lm[nl]]==h[i]){
fg=1;
index=i;
}
}
if(fg&&al[lm[nl]]<=(i-index)*(h[index]<<1)){
int t=(index-lm[nl])*(h[index]<<1);
printf("%d\n",al[lm[nl]]*2+t);
}else{

int t=(i-lm[nl])*(h[lm[nl]]<<1);
printf("%d\n",t+al[lm[nl]]);
}
}else if(h[lm[nl]]>h[rm[nr]]){
// debug("ok2\n");
int i=nl;
bool fg=false;
int index=-1;
for(;h[rm[nr]]>=h[i];i--){
if(!fg&&h[rm[nr]]==h[i]){
fg=1;
index=i;
}
}
// debug("%d\n",i);
if(fg&&ar[rm[nr]]<=(index-i)*(h[index]<<1)){
int t=(rm[nr]-index)*(h[index]<<1);
printf("%d\n",ar[rm[nr]]*2+t);
}else{
int t=(rm[nr]-i)*(h[rm[nr]]<<1);
printf("%d\n",t+ar[rm[nr]]);
}
}else{
int t=min(al[lm[nl]],ar[rm[nr]]);
// debug("%d %d %d\n",al[lm[nl]],ar[rm[nr]],h[rm[nr]]);
printf("%d\n",2*t+(rm[nr]-lm[nl])*(h[rm[nr]]<<1));
}
}
int main() {
ios_base::sync_with_stdio(0);
int r,l;
while(~scanf("%d%d",&l,&r)&&r&&l){
n=(r-l)>>1;
for(int i=0,j=l;i<=n;i++,j+=2){
scanf("%d",&h[i]);
if(j==-1)nl=i;
if(j==1)nr=i;
}
solve();
// Set(ar,0);
// Set(al,0);
}
















}

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