記得先用表單把四個人能走monster不能走monster的步數計起來
然後枚舉每個人當作那個可以踩monster的人,其他人都不能踩
之後再找min最小的就是答案了
//
// GGGGGGGGGGGGG CCCCCCCCCCCCC AAA
// GGG::::::::::::G CCC::::::::::::C A:::A
// GG:::::::::::::::G CC:::::::::::::::C A:::::A
// G:::::GGGGGGGG::::G C:::::CCCCCCCC::::C A:::::::A
// G:::::G GGGGGG C:::::C CCCCCC A:::::::::A
//G:::::G C:::::C A:::::A:::::A
//G:::::G C:::::C A:::::A A:::::A
//G:::::G GGGGGGGGGGC:::::C A:::::A A:::::A
//G:::::G G::::::::GC:::::C A:::::A A:::::A
//G:::::G GGGGG::::GC:::::C A:::::AAAAAAAAA:::::A
//G:::::G G::::GC:::::C A:::::::::::::::::::::A
// G:::::G G::::G C:::::C CCCCCC A:::::AAAAAAAAAAAAA:::::A
// G:::::GGGGGGGG::::G C:::::CCCCCCCC::::C A:::::A A:::::A
// GG:::::::::::::::G CC:::::::::::::::C A:::::A A:::::A
// GGG::::::GGG:::G CCC::::::::::::C A:::::A A:::::A
// GGGGGG GGGG CCCCCCCCCCCCCAAAAAAA AAAAAAA
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <climits>
#include <vector>
#include <set>
#include <map>
#include <queue>
#include <cctype>
#include <utility>
#include <ctime>
using namespace std;
#ifdef DEBUG
#define VAR(a,b) decltype(b) a=(b)
#define debug(...) printf("DEBUG: "),printf(__VA_ARGS__)
#define gettime() end_time=clock();printf("now running time is %.7f\n",(float)(end_time - start_time)/CLOCKS_PER_SEC);
#else
#define VAR(a,b) __typeof(b) a=(b)
#define debug(...)
#define gettime()
#endif
typedef unsigned int uint;
typedef long long int Int;
typedef unsigned long long int UInt;
#define Set(a,s) memset(a,s,sizeof(a))
#define Write(w) freopen(w,"w",stdout)
#define Read(r) freopen(r,"r",stdin)
#define Pln() printf("\n")
#define I_de(x,n)for(int i=0;i<n;i++)printf("%d ",x[i]);Pln()
#define De(x)printf(#x"%d\n",x)
#define For(i,x)for(int i=0;i<x;i++)
#define CON(x,y) x##y
#define Pmz(dp,nx,ny)for(int hty=0;hty<ny;hty++){for(int htx=0;htx<nx;htx++){\
printf("%d ",dp[htx][hty]);}Pln();}
#define M 20
#define PII pair<int,int>
#define PB push_back
#define oo INT_MAX
#define Set_oo 0x3f
#define FOR(a,b) for(VAR(a,(b).begin());a!=(b).end();++a)
#define eps 1e-6
#define X first
#define Y second
clock_t start_time=clock(), end_time;
bool xdy(double x,double y){return x>y+eps;}
bool xddy(double x,double y){return x>y-eps;}
bool xcy(double x,double y){return x<y-eps;}
bool xcdy(double x,double y){return x<y+eps;}
int min3(int x,int y,int z){
int tmp=min(x,y);
return min(tmp,z);
}
int max3(int x,int y,int z){
int tmp=max(x,y);
return max(tmp,z);
}
char tit[10005];
int nx,ny;
int kx[4],ky[4];
int mx,my;
int dx[]={2,1,-1,-2,-2,-1,1,2};
int dy[]={-1,-2,-2,-1,1,2,2,1};
int dis[M][M][10];
int cdis[M][M][10];
void init(){
fill(&dis[0][0][0],&dis[M-1][M-1][9],oo);
for(int k=0;k<4;k++){
queue<PII> q;
q.push(PII(kx[k],ky[k]));
dis[kx[k]][ky[k]][k]=0;
while(!q.empty()){
int x=q.front().X;
int y=q.front().Y;
q.pop();
for(int i=0;i<8;i++){
int nex=x+dx[i],ney=y+dy[i];
if(nex>=nx||nex<0||ney>=ny||ney<0)continue;
if(nex==mx&&ney==my)continue;
if(dis[x][y][k]+1<dis[nex][ney][k]){
dis[nex][ney][k]=dis[x][y][k]+1;
q.push(PII(nex,ney));
}
}
}
}
fill(&cdis[0][0][0],&cdis[M-1][M-1][9],oo);
for(int k=0;k<4;k++){
queue<PII> q;
q.push(PII(kx[k],ky[k]));
cdis[kx[k]][ky[k]][k]=0;
while(!q.empty()){
int x=q.front().X;
int y=q.front().Y;
q.pop();
for(int i=0;i<8;i++){
int nex=x+dx[i],ney=y+dy[i];
if(nex>=nx||nex<0||ney>=ny||ney<0)continue;
if(cdis[x][y][k]+1<cdis[nex][ney][k]){
cdis[nex][ney][k]=cdis[x][y][k]+1;
q.push(PII(nex,ney));
}
}
}
}
}
int check(int x,int y){
int minans=oo;
for(int i=0;i<4;i++){
int ans=0;
for(int j=0;j<4;j++){
if(j==i){
if(cdis[x][y][j]==oo){
ans=oo;
break;
}
ans+=cdis[x][y][j];
}
else{
if(dis[x][y][j]==oo){
ans=oo;
break;
}
ans+=dis[x][y][j];
}
}
minans=min(ans,minans);
}
return minans;
}
int main() {
ios_base::sync_with_stdio(0);
while(~scanf("%s",tit)){
scanf("%d%d",&ny,&nx);
for(int i=0;i<4;i++){
scanf("%d%d",&ky[i],&kx[i]);
kx[i]--;ky[i]--;
}scanf("%d%d",&my,&mx);
mx--;my--;
init();
int minans=oo;
for(int i=0;i<ny;i++){
for(int j=0;j<nx;j++){
if(mx==j&&my==i)continue;
minans=min(minans,check(j,i));
}
}
puts(tit);
if(minans==oo){
printf("Meeting is impossible.\n");
}else printf("Minimum time required is %d minutes.\n",minans);
}
}
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