uva 10524

高斯運算，題目敘述不知道在講啥......

原來是指列不能夠互換

//
//        GGGGGGGGGGGGG        CCCCCCCCCCCCC               AAA
//     GGG::::::::::::G     CCC::::::::::::C              A:::A
//   GG:::::::::::::::G   CC:::::::::::::::C             A:::::A
//  G:::::GGGGGGGG::::G  C:::::CCCCCCCC::::C            A:::::::A
// G:::::G       GGGGGG C:::::C       CCCCCC           A:::::::::A
//G:::::G              C:::::C                        A:::::A:::::A
//G:::::G              C:::::C                       A:::::A A:::::A
//G:::::G    GGGGGGGGGGC:::::C                      A:::::A   A:::::A
//G:::::G    G::::::::GC:::::C                     A:::::A     A:::::A
//G:::::G    GGGGG::::GC:::::C                    A:::::AAAAAAAAA:::::A
//G:::::G        G::::GC:::::C                   A:::::::::::::::::::::A
// G:::::G       G::::G C:::::C       CCCCCC    A:::::AAAAAAAAAAAAA:::::A
//  G:::::GGGGGGGG::::G  C:::::CCCCCCCC::::C   A:::::A             A:::::A
//   GG:::::::::::::::G   CC:::::::::::::::C  A:::::A               A:::::A
//     GGG::::::GGG:::G     CCC::::::::::::C A:::::A                 A:::::A
//        GGGGGG   GGGG        CCCCCCCCCCCCCAAAAAAA                   AAAAAAA
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <climits>
#include <vector>
#include <set>
#include <map>
#include <queue>
#include <cctype>
#include <utility>
#include <ctime>
using namespace std;
#ifdef DEBUG
#define VAR(a,b) decltype(b) a=(b)
#define debug(...) printf("DEBUG: "),printf(__VA_ARGS__)
#define gettime() end_time=clock();printf("now running time is %.7f\n",(float)(end_time - start_time)/CLOCKS_PER_SEC);
#else
#define VAR(a,b) __typeof(b) a=(b)
#define debug(...)
#define gettime()
#endif
typedef unsigned int uint;
typedef long long int Int;
typedef unsigned long long int UInt;
#define Set(a,s) memset(a,s,sizeof(a))
#define Write(w) freopen(w,"w",stdout)
#define Read(r) freopen(r,"r",stdin)
#define Pln() printf("\n")
#define I_de(x,n)for(int i=0;i<n;i++)printf("%d ",x[i]);Pln()
#define De(x)printf(#x"%d\n",x)
#define For(i,x)for(int i=0;i<x;i++)
#define CON(x,y) x##y
#define Pmz(dp,nx,ny)for(int hty=0;hty<ny;hty++){for(int htx=0;htx<nx;htx++){\
    printf("%d ",dp[htx][hty]);}Pln();}
#define M 1005
#define PII pair<int,int>
#define PB push_back
#define oo INT_MAX
#define Set_oo 0x3f
#define FOR(a,b) for(VAR(a,(b).begin());a!=(b).end();++a)
#define eps 1e-6
#define X first
#define Y second
clock_t start_time=clock(), end_time;
bool xdy(double x,double y){return x>y+eps;}
bool xddy(double x,double y){return x>y-eps;}
bool xcy(double x,double y){return x<y-eps;}
bool xcdy(double x,double y){return x<y+eps;}
bool xeqy(double x,double y){return fabs(x-y)<eps;}
int xexy(double x,double y){
    if(x>y+eps)return 2;
    else if(x>y-eps)return 1;
    else if(x<y-eps)return -2;
    else if(x<y+eps)return -1;
    else if(fabs(x-y)<eps)return 0;
    return 3;
}
int min3(int x,int y,int z){
    int tmp=min(x,y);
    return min(tmp,z);
}
int max3(int x,int y,int z){
    int tmp=max(x,y);
    return max(tmp,z);
}
int n,m;
double mz[M][M];
int main() {
    ios_base::sync_with_stdio(0);
    while(~scanf("%d",&n)&&n){
        m=n+n;
        for(int i=0;i<n;i++){
            for(int j=0;j<n;j++){
                scanf("%lf",&mz[j][i]);
            }
            for(int j=n;j<m;j++){
                mz[j][i]=0;
            }
            mz[i+n][i]=1;
        }
        bool suc=true;
        for(int i=0;i<n;i++){
//            for(int j=0;j<n;j++){
//                for(int k=0;k<m;k++)printf("%.2f ",mz[k][j]);
//                Pln();
//            }Pln();
            if(xeqy(mz[i][i],0)){
                suc=false;
                break;
            }
            double t=mz[i][i];
            for(int j=i;j<m;j++){
                mz[j][i]/=t;
            }
            for(int j=0;j<n;j++){
                if(xexy(mz[i][j],0)==0||i==j)continue;
                double t=mz[i][j];
                for(int k=i;k<m;k++){
                    mz[k][j]-=t*mz[k][i];
                }
            }
        }
        if(!suc)puts("Not possible");
        else
            for(int i=0;i<n;i++){
                printf("%.6f",mz[n][i]);
                for(int j=n+1;j<m;j++){
                    printf(" %.6f",mz[j][i]);
                }Pln();
            }
        Pln();
    }

















}